Brake Work Example 12

ACT Work Keys Level: 7
NATEF Task(s): V.D.2; V.D.13; V.D.14

Problem:

You have a customer who wants to be the only person driving around in a Ford truck just the right shade of blue.To ensure a completely unique paint job, you will need to adjust a more traditional paint formula.You use a certain company's specifications for a formula for a single batch of a deep azure blue:

2.6 gallons blue No. 4
3.2 gallons blue No. 6
1¾ gallons yellow No. 1
3 quarts purple No. 1

The color is unique, but to ensure that your customer never encounters another Ford quite the same color, you decide to adjust the formula by reducing all non-blue colors in the mixture by 10% and replacing the loss (same amount) with additional blue No.4.Complicating the matter is the fact that this is a big truck and you will need a triple batch of paint.What will the final formula for this unique paint be?

Solution:

Yellow No. 1: (1¾ gallons)(10% reduction) = (1.75)(0.10) = 0.175 or 0.18 rounded
1.75 – 0.18 = 1.57 gallons of yellow No. 1

Purple No. 1: 3 Quarts = ¾ Gallon

(¾ gallon)(10% reduction) = (0.75)(0.10) = 0.075 or 0.08 rounded
0.75 – 0.08 = 0.67 gallons of purple No. 1

Now, add on the reduction to blue No. 4.
0.18 + 0.08 + 2.6 = 2.86 gallon blue No. 4

So, the single batch formula is:
2.86 gallons blue No. 4
3.2 gallons blue No. 6
1.57 gallons yellow No. 1
0.67 gallons purple No. 1

Now, triple that formula:
(3)(2.86 gallons) = 8.58 gallons blue No. 4
(3)(3.2 gallons) = 9.6 gallons blue No. 6
(3)(1.57 gallons) = 4.71 or 4.7 (rounded) gallons yellow No. 1
(3)(0.67 gallon) = 2.01 or 2.0 (rounded) gallons purple No. 1